Molarity Worksheet W 331 Everett Community College Student Support Services Program What is the molarity of the following solutions given that:
Molarity Problems Worksheet M = _n_ - n= # moles V - V must be in liters (change if necessary) - Use M or mol/L as unit for molarity 1. What is the molarity of a 0
Name _____ Period _____ MOLARITY WORKSHEET #1 For each of the following problems, use proper units and show ALL work:
Molarity Worksheet 1 1. What does molarity mean? 2. What is the molarity of a solution that contains 4.53 moles of lithium nitrate in 2.85 liters of solution?
Name: Worksheet: Classifying Matter Classify each of the materials below. In the center column, state whether the material is a pure substance or mixture. • If the
Conversions between molarity, percent and mg/ml solutions: 8. For a-e, note that NaCl is 58.44 g/mol a) A 1.0 M solution of sodium chloride is __58.44
Mole Worksheet (Key). 1. The average distance between the Earth and Moon is 384,403 km. Using material provided in lab, calculate how many pennies would be needed to stack head to tails to span this distance. *I measured 10 pennies to have a height o
Molarity Practice Problems 1) ... Molarity Practice Problems – Answer Key 1) How many grams of potassium carbonate are needed to make 200 mL of a 2.5 M solution?
Statistics Worksheet Normal Distribution Name:_____ 10. Suppose the test scores of 600 students are normally distributed with a mean of 76 and standard
volume of the box? Here's a picture to show what's happening: Flat piece of cardboard with corners cut out Cardboard folded up to make a box. (a) Let x be the length of each side of the square that is cut out from each corner. This will become the he
Identify each material as either a mixture or pure substance. ... If the material is a pure substance, identify it as an element or a compound. Material. Mixture ... Homogeneous. 9. Pizza. Mixture. Heterogeneous. 10. Blood. Mixture. Heterogeneous. 11
Worksheet 2.1A, Quadratic functions. MATH 1410,. (SOLUTIONS). 1. Find the quadratic function with the given vertex and point. Put your answer in standard form. (a) Vertex (0, 0) passing through (-2, 8). (b) Vertex (2, 0) passing through (1, 3). (c) V
Inverse Variation Worksheet Name:_____ Period:_____ 1. Describe how you determine if a function is a direct variation. 2
Virtual Cell Worksheet- ANSWER KEY. 1. Centrioles are only found in animal cells. They function in cell division. They have 9 groups of 3 ... It also produces lipids for the cell. Draw a picture of the smooth ER. Smooth ER. 7. Cell Membrane performs
1. When we dissolve a cube of sugar in one cup of water, we create a homogeneous mixture. Such mixture is called a solution. The sugar is the solute and water is the solvent. 2. The molarity of a solution is defined as the moles of solute per liter of solution. Molarity is abbreviated as M. When the solvent is water, we have an aqueous solution. 3. A 3 M aqueous calcium nitrate solution contains Ca(NO3) 2 in H2O. We can write the molarity of this solution as unit factor as follows: moles/liter ( mol/L). 4. One liter calcium nitrate solution contains one mole of calcium ions and two moles of nitrate ions. 5. The concentration of a solution can also be expressed in mass percent. A 5% aqueous sodium bromide solution contains 5 grams NaBr in 100g of solution. We can write the mass percent of a solution as a unit factor as follows: grams/grams x 100% (w/w%). 6. What is the number of moles of silver nitrate in a 125 mL solution that is 0.125 M? 0.0156 moles AgNO3 You should recognize from question 2 that 0.125M is the same as 0.125mol/1L. Moles = 125mL soln. x 1L___ x 0.125mol AgNO3 = 0.015625 moles AgNO3 … 3 sig figs… 0.0156 moles 1000mL 1L soln.
7. How many grams of calcium acetate are present in 225 mL solution that is 1.20 M? 42.7g Ca(C2H3O2 )2 225mL soln. x
1L__ x 1.20 mol Ca(C2 H3O2)2 x 158.17 g Ca(C2H3O2)2 = 42.7059… 3 sig figs… 1000mL 1L soln. 1 mol Ca(C2 H3O2)2
8. What mass of glucose, C6H 12O6, is needed to prepare a 250. mL of solution that is 1.50 M glucose solution? Note: the decimal point indicates that the zero is significant. By this point you can probably convert mL to L on your own. 0.250L soln. x 1.50 mol C6H12O6 x 180.18 g C6H12O6 = 67.5675… 3 sig figs… 67.6 g C6H12O6 1L soln. 1 mol C6 H12O6
9. What volume of a 0.150 M NaOH solution contains 2.50 g of sodium hydroxide?
Remember that in dimensional analysis, the numerator and denominator are allowed to trade places so long as the proportion remains the same. (It’s the equivalent of multiplying by 1.) You’ll see here that the molar mass (g/mol) and concentration (mol/L) are ‘upside down.’ If you happened to perform the dimensional analysis beginning with the concentration, you will end up with 1/L or L-1. To get the unit in the right place, you simply need to take invert your answer. That is 1/(1/L) to get L. 2.50 g NaOH. x 1 mol NaOH x X L NaOH = 0.41666… 3 sig figs… 0.417 L NaOH 40.00 g NaOH. 0.150 mol NaOH You can also take the definition of molarity, M = mol/L, and the definition of molar mass, mm=g/mol... solve for mol in the latter (mol =g/mm) and plug it into the former to get M = g/(mm*L). Solving for liters gives L = g/(mm*M). It’s the same!
10. What is the molarity of potassium chlorate prepared my mixing 45.0 g of KClO3 to make 600. mL solution? 45.0 g KClO3. x 1 mol KClO3 x 1 = 1.918 mol/L… 3 sig figs… 1.92 M 39.10 g KClO3. 0.600L soln
11. Given a 2.0 M ammonium sulfide, (NH4)2S: a. What is the molarity of ammonium ions? +
2.0 mol (NH4)2S x 2 mol NH4+_____ = 4.0 mol/L… 2 sig figs… 4.0 M NH4 1 L soln. 1 mol (NH4)2S
b. What is the molarity of the sulfide ions? 2-
2.0 mol (NH4)2S x __1 mol S2-_____ = 2.0 mol/L… 2 sig figs… 2.0 M S 1 L soln. 1 mol (NH4)2S
1
12. What is the molarity of the individual ions in a 225 mL solution that contains 12.5 g of aluminum sulfate? 12.5 g Al2(SO4)3 x _1 mol Al2(SO4)3 x __5 mol ions__ = 0.8118 mol/L … 3 sig figs… 0.812 M total ions 0.225 L soln.
342.17 g Al2(SO4)3
1 mol Al2(SO4)3
13. If 117 g of a compound are dissolved in 500.0 mL of water to give 4.0 M solution, what is the molar mass of this compound? See the explanation in problem 8 on how to use the definition of molar mass and molarity. The equations can be arranged to: mm = g/(L*M) or… g 117 g Unknown x ____1 L soln__ = 58.50 g/mol … 2 sig figs… 58 /mol 0.500 L soln. 4.0 mol Unknown
