Worksheet- Calculations involving Specific Heat 1. For q= m c Δ T : identify each variables by name & the units associated with it. q = amount of heat...
Specific Heat Practice Worksheet 1. An aluminum skillet weighing 1.58 kg is heated on a stove to 173 oC. Suppose the skillet is cooled to room temperature, 23.9 oC
Heat Transfer/ Specific Heat Problems Worksheet ... Place your answer in kJ. 3. The specific heat of iron is ... Determine the specific heat of a certain metal if a
Specific Heat and Heat Capacity Worksheet DIRECTIONS: Use q = (m)(Cp))(ΔT) to solve the following problems. ... if the specific heat of aluminum is 0.90 J/g°C?
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Worksheet- Introduction to Specific Heat Capacities ... Answer questions ... If something has a high specific heat capacity will it take a lot of heat or a little
Specific Heat Worksheet Name (in ink): C = q/mAT, where q = heat energy, m = mass, and T = temperature Remember, AT = (Tfinal — Tinitial). Show all work and proper
Worksheet- Introduction to Specific Heat Capacities ... Answer questions 1. ... *** Specific heat capacity = the amount of heat needed to raise the temperatu re of 1
Specific Heat Capacity Handout Answer Key Objectives ... Example answer: The specific heat of the hot chocolate was 3.9 J/g °C, which is less than the specific
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temperature of 1 g of a substance by 1 oC. Specific heat capacity is a physical characteristic property. Different substances have different specific heats. ... the c value, the more difficult it is to warm up that substance. By the same token, high
Mole Calculations. Chemical Equations and Stoichiometry. Lecture Topics. Atomic weight, Mole, Molecular Mass, Derivation of Formulas, Percent Composition. Chemical Equations and Problems Based on. Miscellaneous Problems, Solution Problems, Review Han
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Worksheet- Calculations involving Specific Heat 1. For q= m ●c ● Δ T : identify each variables by name & the units associated with it. q = amount of heat (J) m = mass (grams) c = specific heat (J/g°C) ΔT = change in temperature (°C) 2. Heat is not the same as temperature, yet they are related. Explain how they differ from each other. Heat is a combination of kinetic energy (measured by temperature) and potential energy. a. Perform calculations using: (q= m ●c ● Δ T) 1. Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of gold from 22 °C to 85 °C? q=? m = 15 g c = 0.129 J/g°C ΔT = 85°C - 22°C = 63°C
b. Determine if it’s endothermic or exothermic 2. An unknown substance with a mass of 100 grams absorbs 1000 J while undergoing a temperature increase of 15 °C. What is the specific heat of the substance? q = 1000 J m = 100 g c=? ΔT = 15°C
3. If the temperature of 34.4 g of ethanol increases from 25 °C to 78.8 °C, how much heat has been absorbed by the ethanol? The specific heat of ethanol is 2.44 J/(g×°C) q=? m = 34.4 g c = 2.44 J/g°C ΔT = 78.8°C - 25°C = 53.8°C 54 °C
4. Graphite has a specific heat of 0.709 J/(g×°C). If a 25 gram piece of graphite is cooled from 35 °C to 18 °C, how much energy was lost by the graphite? q=? m = 25 g c = 0.709 J/g°C ΔT = 18°C - 35°C = -17°C
5. Copper has a specific heat of 0.385 J/(g×°C). A piece of copper absorbs 5000 J of energy and undergoes a temperature change from 100 °C to 200 °C. What is the mass of the piece of copper? q = 5000 J m=? c = 0.385 J/g°C ΔT = 200°C - 100°C = 100°C
6. 45 grams of an unknown substance undergoes a temperature increase of 38 °C after absorbing 4172.4 Joules. What is the specific heat of the substance? Look at the table on page 513 of your book, and identify the substance. q = 4172.4 J m = 45 g c=? ΔT = 38°C
m= 129.87 g 100 g
c = 2.44 J/g°C 2.4 J/g°C Ethanol
Endothermic or exothermic? Endothermic
Endothermic or exothermic? Endothermic
7. A 40 g sample of water absorbs 500 Joules of energy. How much did the water temperature change? The specific heat of water is 4.18 J/(g×°C). q = 500 J m = 40 g c = 4.18 J/g°C ΔT = ?
8. If 335 g of water at 65.5 °C loses 9750 J of heat, what is the final temperature of the water? Liquid water has a specific heat of 4.18 J/(g×°C). q = -9750 J m = 335 g c = 4.18 J/g°C ΔT = Tfinal – 65.5 °C
